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110e2c.jpg
Red Jingling Candy
110e2c
Balanced equation: HC2H3O2 <=> H+ + C2H3O2-
10g NaC2H3O2 = .1219mol, .1219mol in 200.0ml solution = .6095M
Ice table:
[HC2H3O2]| 1.00M, -x, 1.00M-x or 1.00M
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[H+]| 0M, +x, x
[C2H3O2-]| .6095M, +x, .6095M+x or .6095M
Ka = .6095x/1 = 1.7x10^-5
x = [H+] = 2.8x10^-5
pH = -log[H+] = 4.6
Correct me if I'm wrong.
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